All categories

3 years ago

During one year, there were 89,790 births in a large metropolitan area. If

Mathematics

1 answer:

klemol [59]3 years ago

7 0

Answer:

249.4

Bc if you do 89,790 divided by 365 your answer should be 249.4 and some more numbers

You might be interested in

A pizza store offers three different party packages of pizzas. The packages and prices are listed below. If pizzas cost the same

lianna [129]

S+m+l=28
4s+2m+l=58
6s+5m+4l=135

Eliminate the variable l from the first 2 equations

s+m+l=28
-4s-2m-l=-58
-3s-m=-30

Elminiate the variable l from the last 2 equations

6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97

Now solve for s and m using the 2 equations without l

-3s-m=-30
-10s-3m=-97

9s+3m=90
-10s-3m=-97
-s=-7
s=7

Then plug in s into one of the equations without l

-3(7)-m=-30
-21-m=-30
-m=-9
m=9

Now plus in s and m into one of the original 3 equations

(7)+(9)+l=28
16+l=28
l=12

Final answer:
Small=$7
Medium=$9
Large=$12

I know it only asks for large but I wanted to show you how to find them all for future reference. :)

6 0

2 years ago

Read 2 more answers

Find the product of (x + 5)2

tatuchka [14]

You distribute the problem as shown;
2(x+5) 2 times x+2 times 5=2x+10
The answer is 2x+10!

5 0

2 years ago

From these regression results: coefficients standard error t stat intercept 5.6 2.0 2.8 adv 4.9 0.6 9.0 price – 0.5 0.1 – 5.9 su

Margaret [11]

Your so smart you should go to high school

5 0

3 years ago

a number is selected at random from set (2,3,45,6,7,8,9,and 10). which event covers the entire sample space of this experiment ?

ki77a [65]

I'm not sure I understand the question. Is this worded correctly?

8 0

3 years ago

Solution for dy/dx+xsin 2 y=x^3 cos^2y

vichka [17]

Rearrange the ODE as

$\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y$
$\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3$

Take $u=\tan y$ , so that $\dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}$ .

Supposing that $|y|$ , we have $\tan^{-1}u=y$ , from which it follows that

$\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}$
$\sec^2y=1+\tan^2y=1+u^2$

So we can write the ODE as

$\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3$

which is linear in $u$ . Multiplying both sides by $e^{x^2}$ , we have

$e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}$
$\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx$
$e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx$

Substitute $t=x^2$ , so that $\mathrm dt=2x\,\mathrm dx$ . Then

$\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt$

Integrate the right hand side by parts using

$f=t\implies\mathrm df=\mathrm dt$
$\mathrm dg=e^t\,\mathrm dt\implies g=e^t$
$\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)$

You should end up with

$e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C$
$u=\dfrac{x^2-1}2+Ce^{-x^2}$
$\tan y=\dfrac{x^2-1}2+Ce^{-x^2}$

and provided that we restrict $|y|$ , we can write

$y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)$

5 0

3 years ago