The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
The Company A rented the truck for $40 a day plus $0.40 per miles
The expression will be
40+0.40x
Where x is the number of miles
The company B rented the truck for $20 a day plus $0.50 per miles
20+0.50x
To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be
40+0.40x = 20+0.50x
40-20 = 0.50x-0.40x
0.1x = 20
x = 200 miles
Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
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Answer:
13/28.
Step-by-step explanation:
(8/14 - 2/8) + 1/7
We can just remove the parentheses and simplify its contents:
= 4/7 - 1/4 + 1/7
= 4/7 + 1/7 - 1/4
= 5/7 - 1/4 The LCD of 7 and 4 is 28 so we have:
20/28 - 7/28
= 13/28.
Answer: A = -2/5
Step-by-step explanation:
- 6/5 - 2/5 = - 8/5 aka - 1 3/5
-1 3/5 ÷ 4 = - 2/5
Answer:
-8
Step-by-step explanation:
1/2 times 10 is 5. and a negative times a negative is a positive, so you have a positive 12, which becomes 5+12-25, which is -8
