If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Well just substitute y (the first equation) into the second equation.
So
5x-4(5-3x)=-3
Then just solve the equation from there.
5x-20+12x=-3
17x=17
x=1
and if you need y, y=2
The answer is x=-20.
6+ -28 -x =-2
You first add 28 to each side=6+-x=26 then you minus 6 from each side=-x=20.
Then you divide 20 by -x resulting in x=-20
Answer: The journey took 4 hours and 15 minutes.
Let 1 number equal x
<span>Let the other number equal 1/2x + 6
x + (1/2x + 6) =21
1 & 1/2 x + 6 =21
1 & 1/2 x =15
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