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3 years ago

26. The first half of a play is 35 minutes longer than the second half of the play. If

1 answer:

7 0

155-35= 120 (you subtract 35 so you get the number if both plays lasted the same time )
120/2= 60 (you get the amount of time one play lasted without extra 35 minutes)
60+35=95 (then add 35 minutes to one play because 1 one is longer than the other one)

the first half of the play is 95 minutes long.

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3 years ago

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Which expression is equivalent to 13b+23b−56(b+1)?

ale4655 [162]

Start by combining LIKE-TERMS. 13b AND 23 are LIKE-TERMS because they have the same variable (B) and numbers. Remember PEMDAS OR Please Excuse My Dear Aunt Sally. (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There is also FOIL (First, Inside, Outside, Last). Because we will start with Parenthesis(Use the FOIL method because the 56 is part of the parentheses) first, (-56 x b[first part of the set]) = -56b THEN (-56 x [+ {always carry the sign, this shows that it is positive}]1) = -56

Now we have 13b+23b -56b-56
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3 years ago

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25 km 7 km 18 km 24 km Find the area!!

Anna35 [415]

Answer:

75600k^4 m^4 Hope that help !

Step-by-step explanation:

1. Take out the constants (25×7×18×24) kkkkmmmm

2. Simplify 25×7=175 (175×18×24)kkkkmmmm

3. Simplify 175×18=3150 (3150×24)kkkkmmmm

4. 3150×24= 75600kkkkmmmm

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3 years ago

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Len [333]

Answer:

Step-by-step explanation:

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3 years ago

(3 points)

Snezhnost [94]

Answer:

The exponential Function is $20+12h=200$ .

Farmer will have 200 sheep after 15 years.

Step-by-step explanation:

Given:

Number of sheep bought = 20

Annual Rate of increase in sheep = 60%

We need to find that after how many years the farmer will have 200 sheep.

Let the number of years be 'h'

First we will find the Number of sheep increase in 1 year.

Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.

framing in equation form we get;

Number of sheep increase in 1 year = $\frac{60}{100}\times20 = 12$

Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years is equal to 200.

Framing in equation form we get;

$20+12h=200$

The exponential Function is $20+12h=200$ .

Subtracting both side by 20 using subtraction property we get;

$20+12h-20=200-20\\\\12h=180$

Now Dividing both side by 12 using Division property we get;

$\frac{12h}{12} = \frac{180}{12}\\\\h =15$

Hence Farmer will have 200 sheep after 15 years.

6 0

3 years ago