30÷5=6
4×5=20
for every 30 green lights there are 20 white lights
A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
The prime factorization is 3 x 3 x 5 x 13
Answer:
2 hours 30 minutes
Step-by-step explanation:
210 - 30 = 190
190 / 75 = 2.5
Sorry if I'm wrong.
