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3 years ago

Combine like terms, then simplify if need be. 4cx + cx – cx – cx + cx

Mathematics

2 answers:

Crank3 years ago

8 0

Answer:

4cx

hope this helps

have a good day :)

Step-by-step explanation:

madreJ [45]3 years ago

4 0

A common technique for simplifying algebraic expressions when combining like terms such as 2X and 3X we are there confections for an example 2x+3x=(2+3)x=5x

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Suppose that the revenue function for a certain product is given by R(x) = 17(2x + 1)−1 + 34x − 17 where x is in thousands of un

REY [17]

Answer:

Step-by-step explanation:

Given that:

R(x) = $\frac{17}{2x+1}$ + 34x − 17

As we know that derivative of revenue function is marginal revenue function .

We will use following rules of derivative

=> dR/ dx = $\frac{-17*2}{(2x+1)^{2} } + 34$

=> R' (x) = $\frac{-34}{(2x+1)^{2} } + 34$

=> R '(2000) = $\frac{-34}{(2*2000+1)^{2} } + 34$ = 34

The revenue when 2000 units are sold is:

R(2000) = $\frac{17}{2*2000+1}$ + 34*2000 − 17 = $69,783

3 0

2 years ago

What is required in aerobic respiration?<br>

likoan [24]

O2, or Oxygen, and C6H12O6, or glucose.

6 0

2 years ago

Apply the distributive property to factor out the greatest common factor.<br> 45e -27f

mojhsa [17]

Answer:

9 (5e - 3f)

Step-by-step explanation:

45e -27f

45e = 9*5*e

27f = 9*3*f

The common factor is 9

9*5*e - 9*3*f

9 (5e - 3f)

8 0

2 years ago

Read 2 more answers

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$