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bekas [8.4K]
3 years ago
13

Can someone please help me with this answer

Mathematics
1 answer:
iragen [17]3 years ago
5 0
The correct answer is C
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Need help on number 8 plz
Vilka [71]

I believe the answer is

<h2>D.</h2>

<u>''Twice as many students will take art as will take choir''</u>

<u />

<h3>There are 80 students taking art, and 40 students taking choir. </h3><h3>Art is twice the size of choir.</h3><h3 />

(I'm giving away free points in my question)

I hope this helped! +*♡

8 0
3 years ago
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Y&lt; 3x + 6<br> Determine if (2,4) is a solution
kap26 [50]

Answer:

Yes

Step-by-step explanation:

4 < 3(2) + 6

4< 6+6

4 < 12

3 0
3 years ago
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-2x + y = 4<br> y = x + 2<br><br><br> Third question^ solve the system of equations
Leya [2.2K]

Answer:

x=-2 y=0

Step-by-step explanation:

put the second equation in to the first one

-2x+x+2=4

-x=2

x=-2

y=-2+2=0

x=-2 y=0

6 0
3 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
3 years ago
Evaluate a + b for a = 12 and b = 6.
den301095 [7]

Answer:

Here,

a= 12

b = 6

Then,

a+b

= 12 + 6

= 18

.°. 18 is the solution

3 0
3 years ago
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