The probability of one success and one failure will be 4/9. Table C represents the probability distribution for the variable X.
<h3>What is probability?</h3>
The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,
The dials on the spinner are spun 2 times in a row.
P(dial lands on region)=P(success) = 2/3
P(failure) = 1/3
The probability that the two times dials on the spinner are not spun 2 times in a row.
P = (1/3)² = 1/9
The probability that the two times dials on the spinner are spun 2 times in a row.
P = (2/3)²= 4/9
One may calculate the probability of one success and one failure using the binomial distribution or by simply deducting the probabilities we previously determined from 1.
P = 1 - 1/9 - 4/9
P = 4/9
The probability of one success and one failure will be 4/9.
Hence table C represents the probability distribution for the variable
X.
To learn more about the probability, refer to the link;
brainly.com/question/11234923
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Rational exponents work as follows:
![a^{\frac{b}{c}}=\sqrt[c]{a^b}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bb%7D%7Bc%7D%7D%3D%5Csqrt%5Bc%5D%7Ba%5Eb%7D)
So, in your case, we have
![(x^3y^5)^{\frac{4}{3}} = \sqrt[3]{(x^3y^5)^4}=\sqrt[3]{x^{12}y^{20}}=\sqrt[3]{x^{12}y^{18}\cdot y^2}}=x^4y^6\sqrt[3]{y^2}](https://tex.z-dn.net/?f=%28x%5E3y%5E5%29%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%28x%5E3y%5E5%29%5E4%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B12%7Dy%5E%7B20%7D%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B12%7Dy%5E%7B18%7D%5Ccdot%20y%5E2%7D%7D%3Dx%5E4y%5E6%5Csqrt%5B3%5D%7By%5E2%7D)
1/3 3 or 2 i just know its not the cannot be determined one i got it wrong
Given:
In triangle ABC, right angle at angle C.
meters

To find:
The measure of side c.
Solution:
In a right angle triangle,

It is also written as:

In triangle ABC, angle C is a right angle. It means the side c is the hypotenuse.
In triangle ABC,



On further simplification, we get



Therefore, the measure of side c is 68.07 meters.
5(2y - 2) + 4 Distribute/multiply 5 into (2y - 2)
(5(2y) - 5(2)) + 4
10y - 10 + 4 Combine like terms (-10 + 4)
10y - 6