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icang [17]
3 years ago
7

147.1 is what percent of 155

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
Solution for what is 147.1% of 155

155/x=100/147.1
(155/x)*x=(100/147.1)*x       - we multiply both sides of the equation by x
155=0.67980965329708*x       - we divide both sides of the equation by (0.67980965329708) to get x
155/0.67980965329708=x 
228.005=x 
x=228.005

now we have: 
147.1% of 155=228.005

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Marta_Voda [28]

Answer:

1 tablet

Step-by-step explanation:

Data provided in the question:

The dose of the Uniphyl = 5 mg/kg

Strength of the Uniphyl = 400 mg per tablet

Weight of the patient = 76 kg

Now,

The recommended dose for the patient            

= Dose of the Uniphyl × weight of the patient

= 5 mg/kg × 76 kg

= 380 mg

Therefore,

The number of tablets to be administered to the patient

= \frac{\textup{Recommended dose for the patient}}{\textup{Strength of the Uniphyl}}

= \frac{\textup{380}}{\textup{400}}

= 0.95 ≈ 1 tablet

Hence,

The number of tablets to be administered to the patient is 1

7 0
3 years ago
Aiden calculated the area of triangle QRS below by finding half the product of 1.5 and 1.1. Triangle Q R S has a base of 5.4 and
Orlov [11]

Answer:

i

Step-by-step explanation:

8 0
3 years ago
Julio's wages vary directly as the number of hours that he works. if his wages for 5 hours are $29.75, how much will he earn for
OlgaM077 [116]

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$178.50

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What is the 2nd term when −3f3 + 9f + 6f4 − 2f2 is arranged in descending order?
Brilliant_brown [7]

For this case we have the following polynomial:

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To answer the question, what we must do is rewrite the polynomial in its standard form.

We have then that the polynomial will be given by:

6f ^ 4 - 3f ^ 3 - 2f ^ 2 + 9f

Therefore, we have the ordered polynomial in descending form of exponents.

Therefore, the second term of the polynomial is:

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Answer:

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6 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
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