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3 years ago

Find the slope of the line that contains the points (-9, 4) and (-7, -2).

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

Answer:

-3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-4)/(-7-(-9))

m=-6/(-7+9)

m=-6/2

m=-3

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4x^2-400=0 square roots and solving quadratics

posledela

Answer:

x = ±10

Step-by-step explanation:

4x² - 400 = 0

Add 400 to both sides

4x² = 400

Divide both sides by 4

x² = 100

Take the square root of both sides

x = ±10

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3 years ago

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Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

Answer Check

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$

The equation is true for both roots.

Answer

$\large \boxed {3 {x}^{2} - 14x - 5 = 0}$

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Answer:

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3 years ago

Wxyz is a rectangle. what is zx?

Nitella [24]

ZX is the diagonal :)
Hope this helped!

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