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3 years ago

Which type of transformation is described by (x, y) (x+2, y+3)

Mathematics

1 answer:

Readme [11.4K]3 years ago

3 0

This is a translation. It moves two to the right and three up.

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Solve the inequality 15 ≥ q + 3

oksano4ka [1.4K]

Answer:

$q\le \:12$

Step-by-step explanation:

<u>Solving</u>

$\mathrm{Switch\:sides}$ (Not a required step)

$q+3\le \:15$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$q+3-3\le \:15-3\\=q\le \:12$

$\bold{q\le \:12}$

<u>Graphing</u>

5 0

2 years ago

Help & explain answer pls

AlekseyPX

The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)

5 0

2 years ago

What is equivalent to 32

frez [133]

Answer:

32.0 or 32/1 or 64/2

4 0

3 years ago

Read 2 more answers

How to get the answer for 2 3/4 gallons and 5/8 to equal 1 23/32

Alecsey [184]

Answer:

jhwgehebf

Step-by-step explanation:

bwjsfehoal topu

7 0

2 years ago

write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i

inessss [21]

Answer:

$f(x)=3x^3+x^2+3x+1$

Step-by-step explanation:

If a real number $-\frac{1}{3}$ is a zero of polynomial function, then

$x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}$

is the factor of this function.

If a complex number $-i$ is a xero of the polynomial function, then the complex number $i$ is also a zero of this function and

$x-(-i)=x+i\ \text{ and }\ x-i$

are two factors of this function.

So, the function of least degree is

$f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)$

If the polynomial function must be with integer coefficients, then it has a form

$f(x)=3x^3+x^2+3x+1$

4 0

3 years ago