If 1-√3 cot (x+15°)=0, find the acute angle x

1 answer:

True [87]3 years ago

5 0

1 - √3 cot (x + 15) = 0

√3 cot(x + 15) = 1

tan (x + 15) = √3

x + 15 = 60

x = 45 degrees answer

You might be interested in

trasher [3.6K]

Yes this is a function

8 0

3 years ago

Usimov [2.4K]

Step-by-step explanation:

26. x²+5x+25/4 = (x + 5/2)²

29. x²/4y²-2/3+4y²/9x² = (x/2y - 2y/3x)²

6 0

2 years ago

sashaice [31]

What is the essential question?

8 0

3 years ago

Rashid [163]

A. g(10)= -29
b.f(3)=16
c.h(-2)=-6
d.j(7)=23
e.h(a)=12/a
f. g(b+c)=-3b-3c+1 ...etc I'm bored

3 0

3 years ago

UkoKoshka [18]

Answer:

hypotenuse:2 (AB)

adjacent side: 1 (AD)

opposite side:√3(BD)

Step-by-step explanation:

-->AB is hypotenuse cuz it's opposite to right angle (90°)

-->AD is adjacent,cuz it's adjacent to reference angle(60°)

-->BD is opposite side,cuz it's opposite to the reference angle(60°)

✌️:)

4 0

3 years ago