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marissa [1.9K]
3 years ago
7

The population of a small town is 40,740. It's population falls by 8% per year. How many years later will the population be 14,5

50? (Assume that the growth rate is annualized and use the formula for compound growth: A = P ( 1 + r n ) n t . If the compounding frequency is not given, use n = 1 .)
Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

0.9101523758 ≈ 1 year

Step-by-step explanation:

The population of a small town is 40,740.

Its population falls by 8% per year.

Given: Compound interest Amount (A) = P( 1 + \frac{r}{n})^{nt}

14,550 = 40,740(1 + \frac{-8}{100 * 1})^{t*1}

14,550 = (40,740 - 3259.2)^{t}

14,550 = (37,480.8)^{t}

t * log 37,480.8 = log 14,550

t = \frac{ log 14,550}{log 37,480.8} = 0.9101523758 ≈ 1 year

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