3 years ago

Someone help PLEASE

Mathematics

1 answer:

Iteru [2.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

The perfect square:

$(a+b)^2=a^2+2ab+b^2$

We have

$y^2+14y+49=0\\\\y^2+2(y)(7)+7^2=0\\\\(y+7)^2=0\iff y+7=0\qquad\text{subtract 7 from both sides}\\\\\boxed{y=-7}$

We have

$y^2+16y+64=0\\\\y^2+2(y)(8)+8^2=0\\\\(y+8)^2=0\iff y+8=0\qquad\text{subtract 8 from both sides}\\\\\boxed{y=-8}$

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