Step-by-step explanation:
If I'm understanding what a "proof" means, some answers could be:
2 + 3 = 5
4 + 15 = 19
8 + 21 = 29
Hope this helps you! Have a good night!
Put the values of m and p to the expression:
Answer:
The answer should be .25
Step-by-step explanation:
The answer should be .25 because:
- there are 4 places you can score and since you want it to land on 5 and there is only one 5 it counts as a 1
- the since there are 4 in total and you want to land on 1 you get 1/4 the number one standing for there only being one 5 and the 4 standing for the number of places to land on.
-then you convert the 1/4 into a decimal which makes .25
Answer:
a) P(2)=0.270
b) P(X>3)=0.605
c) P=0.410
Step-by-step explanation:
We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:
![\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}](https://tex.z-dn.net/?f=%5Cboxed%7BP%28k%29%3D%5Cfrac%7B%5Clambda%5Ek%20%5Ccdot%20e%5E%7B-%5Clambda%7D%7D%7Bk%21%7D%7D)
a) In this case: ![\lambda=2.1](https://tex.z-dn.net/?f=%5Clambda%3D2.1)
![P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270](https://tex.z-dn.net/?f=P%282%29%3D%5Cfrac%7B2.1%5E2%20%5Ccdot%20e%5E%7B-2.1%7D%7D%7B2%7D%5C%5C%5C%5CP%282%29%3D0.270)
Therefore, the probability is P(2)=0.270.
b) In this case: ![\lambda=2\cdot 2.1=4.2](https://tex.z-dn.net/?f=%5Clambda%3D2%5Ccdot%202.1%3D4.2)
![P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605](https://tex.z-dn.net/?f=P%28X%3E3%29%3D1-P%28X%5Cleq%203%29%5C%5C%5C%5CP%28X%3E3%29%3D1-%5Csum_%7Bx%3D0%7D%5E3%20%5Cfrac%7B4.2%5Ex%20%5Ccdot%20e%5E%7B-4.2%7D%7D%7Bx%21%7D%5C%5C%5C%5CP%28X%3E3%29%3D1-0.395%5C%5C%5C%5CP%28X%3E3%29%3D0.605)
Therefore, the probability is P(X>3)=0.605.
c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.
In this case: ![\lambda=2\cdot 2.1=4.2](https://tex.z-dn.net/?f=%5Clambda%3D2%5Ccdot%202.1%3D4.2)
![P(X\geq 5)=1-P(X](https://tex.z-dn.net/?f=P%28X%5Cgeq%205%29%3D1-P%28X%3C5%29%5C%5C%5C%5CP%28X%5Cgeq%205%29%3D1-P%28X%5Cleq%204%29%5C%5C%5C%5CP%28X%5Cgeq%205%29%3D1-%5Csum_%7Bx%3D0%7D%5E4%20%5Cfrac%7B4.2%5Ex%5Ccdot%20e%5E%7B-4.2%7D%7D%7Bx%21%7D%5C%5C%5C%5CP%28X%5Cgeq%205%29%3D1-0.590%5C%5C%5C%5CP%28X%5Cgeq%205%29%3D0.410)
Therefore, the probability is P=0.410.
Answer:
i think its -1
Step-by-step explanation:
sorry if im wrong