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inna [77]
3 years ago
8

The Cost Saver Grocery Club sells sheet cakes. Each 14 sheet of cake requires 0.75 teaspoon of baking soda.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

2.75 tsp

Step-by-step explanation:

1/4 divided by 0.75

Zarrin [17]3 years ago
3 0

you gay and I don't knownjow to don't his

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What is the quotient of<br> 3/4 and 1/5
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3.75

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Hi can someone please answet this question for me im a bit confused
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a)

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Please help me with this SHOW WORK ON PAPER
yawa3891 [41]

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answers and work are shown below:)

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3 years ago
Read 2 more answers
Does this look correct?
Neko [114]
That is not correct.  I will help you.  Begin by subtracting the 9x from both sides, like this:  9x - 9x + 2y = 6 - 9x.  That simplifies to 2y = -9x + 6.  Now divide both sides by 2 to get y all alone, like this:  \frac{2y}{2}=- \frac{9}{2}x+ \frac{6}{2}.  That reduces down to y=- \frac{9}{2}x+3.  That is slope-intercept form.  y = mx + b.
7 0
3 years ago
The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si
OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!

a) The probability that exactly 3 arrivals occur during a particular hour is:

P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938

c) In this case, t=0.25, so we recalculate the parameter as:

\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

E(x)=\lambda=1.5

3 0
3 years ago
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