The amount of rim needed for each window is 141.4 in
<h3>How to find the length of the outer rim?</h3>
Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.
<h3>What is an arc?</h3>
An arc is part of section of the circumference of a circle
<h3>What is the length of an arc?</h3>
So, length of arc, L = Ф/360 × 2πR where
- Ф = central angle of arc and
- R = radius of circle.
Gven that for the window rim
- Ф = angle of the rim = 270° and
- R = radius of the rim = 30 in
Substituting the values of the variables into the equation for L, we have
L = Ф/360 × 2πR
L = 270°/360° × 2π × 30 in
L = 3/4 × 2π × 30 in
L = 3/2 × π × 30 in
L = 3 × π × 15 in
L = 45π in
L = 141.37 in
L ≅ 141.4 in
So, the amount of rim needed for each window is 141.4 in
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Pretty sure the answer is 6
Answer:
Yes
Step-by-step explanation:

Answer:
b) 690 - 7.5*t
c) 0 < t < 92s time (t) is independent quantity
d) 0 < s < 690ft distance from bus stop (s) is dependent quantity
e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop
Step-by-step explanation:
Part a - see diagram
part b
initial distance from bus stop s0 = 690 ft
distance covered = 7.5*t
s = s0 - distance covered
s = 690 - 7.5*t = f(t)
part c
s = 0 or s = 690
0 = 690 -7.5*t
t = 92 s
Hence domain : 0 < t < 92s time (t) is independent quantity
part d
s = 0 or s = 690
Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)
part e
f(0) is s @t = 0
f(0) = 690 ft away from bus stop
f(60.25) is s @t = 60.25
f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.