Answer:
The average value of the function
over the interval
is
.
Step-by-step explanation:
The average value of a function over an interval is represented by this integral:

Where:
,
- Lower and upper bounds of the interval, dimensionless.
- Function, dimensionless.
If
,
and
, the average value of the function is:



![\bar y = \frac{6}{5}\cdot [4-(-1)]- \frac{1}{15}\cdot [4^{3}-(-1)^{3}]](https://tex.z-dn.net/?f=%5Cbar%20y%20%3D%20%5Cfrac%7B6%7D%7B5%7D%5Ccdot%20%5B4-%28-1%29%5D-%20%5Cfrac%7B1%7D%7B15%7D%5Ccdot%20%5B4%5E%7B3%7D-%28-1%29%5E%7B3%7D%5D)

The average value of the function
over the interval
is
.
Substitute the first equation, y = 1.9x - 6 into the second one for y.
3(1.9x - 6) = 5.7x - 18
Distribute the 3.
5.7x - 18 = 5.7x - 18
This means that there are infinite solutions, since the two equations are the exact same lines.
Hope this helps!
Answer:
2hours and 17 minutes
Step-by-step explanation:
Slope=10/9 . y-intercept= -5. so equation would be y=10/9x-5
C, please help me on mine