Answer:
![12y+x-12=0](https://tex.z-dn.net/?f=12y%2Bx-12%3D0)
Step-by-step explanation:
If I'm not mistaken by the question, we have
![x+4y=\dfrac{2}{3}x+4](https://tex.z-dn.net/?f=x%2B4y%3D%5Cdfrac%7B2%7D%7B3%7Dx%2B4)
Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)
![3\timesx+3\times4y=3\times\dfrac{2}{3}x+3\times4](https://tex.z-dn.net/?f=3%5Ctimesx%2B3%5Ctimes4y%3D3%5Ctimes%5Cdfrac%7B2%7D%7B3%7Dx%2B3%5Ctimes4)
![3x+12y=2x+12](https://tex.z-dn.net/?f=3x%2B12y%3D2x%2B12)
Putting all terms on the LHS (left hand side) and evaluating,
![12y+x-12=0](https://tex.z-dn.net/?f=12y%2Bx-12%3D0)
Parallelograms, rectangles, rhombus, or square
Answer:
2.10 is greater than 2.09
Step-by-step explanation:
because 2.10 has more equation than 2.09
Answer:
I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.
- Lower bound = 1914.8
- Upper bound = 999999
- Mean = 1986.1
- Standard deviation = 27.2
Input in these values and it will result in:
normCdf(1914.8,9999999,1986.1,27.2) = 0.995621
So the probability that the value is greater than 1914.8 is about 99.5621%
<u><em>I'm not sure if this is correct </em></u><em>0_o</em>