The fraction 4/5 is equivalent to 0.8 and 80%.
Write 0.8 and 80% as unreduced fractions.
0.8 = 8/10
80% = 80/100
<C = 180 - 32
<C = 148 degrees
(<C+<D = 180)
2 + 4x + 5 = 0
4x + 2 + 5 = 0
4x + 7 = 0
4x = 0 - 7
4x = -7
x = <u> </u><u>-7</u><u> </u> ANSWER
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Answer:
Depends on what way you learnt it
Step-by-step explanation:
x + y = 4. x^2 + y^2 = 28. These are the given equations.
Square the first equation to get x^2 + 2xy + y^2 = 16.
Subtract the new equation from x^2 + y^2 = 28 to get 2xy = -12.
Divide by 2 to get xy = -6. The questions asks for positive numbers, and a positive times a positive is not a negative, therefore there are no two numbers.
We are given
length of sides are
AB=7
AC=7
BC=6
now, we can use formula of area of triangle
![A=r*s](https://tex.z-dn.net/?f=%20A%3Dr%2As%20)
where
A is area of triangle
r is radius of in-circle
s is semi-perimeter of triangle
step-1: Finding area of triangle
We can use
Heron's formula
![s=\frac{a+b+c}{2}](https://tex.z-dn.net/?f=%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%20%20)
a , b and c are values of sides
![A=\sqrt{s(s-a)(s-b)(s-c)}](https://tex.z-dn.net/?f=%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%20%20)
now, we can plug values
![A=\sqrt{10(10-7)(10-7)(10-6)}](https://tex.z-dn.net/?f=%20A%3D%5Csqrt%7B10%2810-7%29%2810-7%29%2810-6%29%7D%20%20)
![A=6\sqrt{10}](https://tex.z-dn.net/?f=%20A%3D6%5Csqrt%7B10%7D%20%20)
step-2: Finding radius(r)
we got
![A=6\sqrt{10}](https://tex.z-dn.net/?f=%20A%3D6%5Csqrt%7B10%7D%20%20)
now, we can find radius
![A=r*s](https://tex.z-dn.net/?f=%20A%3Dr%2As%20)
![6\sqrt{10} =r*10](https://tex.z-dn.net/?f=%206%5Csqrt%7B10%7D%20%3Dr%2A10%20)
............Answer