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ozzi
3 years ago
15

High school students from grades 9–10 and 11–12 were asked to choose the kind of band to have play at a school dance: rap, rock,

or country.
Their choices were as follows:
Grades 9–10—Rap: 40; Rock: 30; Country: 55
Grades 11–12—Rap: 60; Rock: 25; Country: 35

Find a correct two-way frequency table for the data
Mathematics
2 answers:
yanalaym [24]3 years ago
8 0
The correct two-way frequency table for the date will look like this:
                 
                               RAP      ROCK     COUNTRY     TOTAL
Grades 9-10           40           30            55                  125
Grades 11-12         60           25            35                  120
TOTAL                    100          55            90                  245

The sum of the row total is equal to the sum of the column total
125 + 120 = 100 + 55 + 90
245 = 245
r-ruslan [8.4K]3 years ago
8 0

Answer:C

Step-by-step explanation:

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3 more than a number then divided the result by 8
ziro4ka [17]

We are given statement : 3 more than a number then divided the result by 8.

We need to write an algebraic expression for it.

Let us assume unknown number be n.

3 more than n = (n+3).

Now, we need to divide that result (n+3) by 8.

So, we would get (n+3) divided by 8 = \frac{n+3}{8}.

<h3>Therefore, final expression is \frac{n+3}{8}.</h3>
5 0
3 years ago
Read 2 more answers
Please help me with the worksheet
aivan3 [116]

Answer:

9)    a = ¾, <u>vertex</u>: (-4, 2),  <u>Equation</u>: y = ¾|x + 4| + 2

10)  a = ¼, <u>vertex</u>: (0, -3),  <u>Equation</u>: y = ¼|x - 0| - 3

11)   a = -4,  <u>vertex</u>: (3,  1),   <u>Equation</u>: y = -4|x - 3| + 1

12)  a = 1,    <u>vertex</u>: (-2, -2),  <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

<h3><u>Note:</u></h3>

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a|  = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9)  ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>:  y = ¾|x + 4| + 2

<h3>Question 10)  ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a  

Divide both sides by 4 to solve for <em>a</em>:

\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>:  y = ¼|x - 0| - 3

<h3>Question 11)  ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>:  y = -4|x - 3| + 1

<h3>Question 12)  ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2  = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>:  y = |x + 2| - 2

5 0
2 years ago
The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be mov
Mandarinka [93]

Answer:

a) C(M,D) = KMD

b) $12,000                  

Step-by-step explanation:

We are given the following information in the question:

The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be moved.

This can be written as:

a)

C \propto M\times D\\C = KMD,\\\text{where K is the constant of proportionality.}

C(M,D) = KMD

b) It costs 50 dollars to move 1 ton of rubble 1 mile

50 = K\times 1\times 1\\\Rightarrow K= 50

We have to find  cost to move 16 tons 15 miles.

Putting the values in the function:

C(16,15) = 50\times 16\times 15 = 12000

Thus, $12,00 is the cost to move 16 tons 15 miles.

3 0
3 years ago
5(x+6)+11=25-3x what is the answer?
Zolol [24]
This is how I did it:
5(x + 6) + 11 = 25 - 3x          use distribution
5x + 30 + 11 = 25 - 3x          use addition
5x + 41 = 25 - 3x                  use addition and subtraction
8x = -16                                use division
x = -16/8
x = -2

So your answer is x = -2


3 0
3 years ago
The speed of cars on a stretch of road is normally distributed with an average 51 miles per hour with a standard deviation of 5.
Oliga [24]

Answer: 0.57

Step-by-step explanation:

Given : The speed of cars on a stretch of road is normally distributed .

Population Mean = \mu=51\text{ miles per hour}

Standard deviation : \sigma= 5.9\text{ miles per hour}

Let x be the random variable that represents the speed of cars on a stretch of road .

z-score : z=\dfrac{x-\mu}{\sigma}

For x= 50.

z=\dfrac{50-51}{5.9}\approx-0.17

By using the standard normal distribution table ,

The probability that a randomly selected car is violating the speed limit of 50 miles per hour :-

P(x>50)=1-P(x\leq50)=1-P(z\leq-0.17)\\\\=1- 0.4325051=0.5674949\approx0.57\\

5 0
3 years ago
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