Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –Two-thirds(x – 6) and passes through the point (−2, −2)? y = –Two-thirdsx – Ten-thirds y = –Two-thirdsx + Ten-thirds y = Three-halvesx – 1 y = Three-halvesx + 1

Answer 1

Answer:

y=3/2x +1  ⇒⇒Three-halves *x+1

Answer 2

The equation is y = Three-halvesx + 1

Step-by-step explanation:

That line should be perpendicular to the given line : y-4 = -2/3 (x-6) and

It passes through (-2,-2)

Write the equation in slope-intercept form as;

y-4= -2/3 (x-6)

y-4=-2/3x + 4

y= -2/3x + 8

The slope m₁, of the equation is -2/3

For perpendicular lines, m₁*m₂= -1

So,finding m₂ where m₁ = -2/3

-2/3 * m₂ = -1

m₂ = -1 * - 3/2 = 3/2

The equation of the line passing through point (-2,-2) with m₂=3/2 will be;

y--2/x--2 = 3/2

y+2/x+2=3/2

2(y+2)=3(x+2)

2y+4=3x+6

2y=3x+6-4

2y=3x+2

y=3/2x +1  ⇒⇒Three-halves *x+1

Learn More

Equation of perpendicular lines : brainly.com/question/11482954

Keyword : equation, slope-intercept form, perpendicular

#LearnwithBrainly