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3 years ago

3x^2 - 4x - 5x^2 + 8x simplify it please

Mathematics

1 answer:

Levart [38]3 years ago

3 0

$3x^2 - 4x - 5x^2 + 8x$

Set up

$-2x^2 + 4x$

Combine like terms

$2x(-x + 2)$

Take out a common factor

$2x(2 - x)$

Rearrange to remove a starting negative coefficient inside the parentheses

The simplification is $\boxed{2x(2 - x)}$ .

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3 years ago

I need to verify identity functions for a one to one function.

Eddi Din [679]

We have the function

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1. For f^-1:

Let y = f(x) = (x+6)^3

Switch x and y to get:

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$\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}$

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Answer blank 1:

$f^{-1}(x)=x^{\frac{1}{3}}-6$

2. For f o f^-1 (x):

$(f\circ f^{-1})(x)=f(f^{-1}(x))$

And solve

$\begin{gathered} =f(x^{\frac{1}{3}}-6) \\ =(x^{\frac{1}{3}}-6+6)^3 \\ =(x^{\frac{1}{3}})^3 \\ =x \end{gathered}$

answer blank 2

$x^{\frac{1}{3}}-6$

answer blank 3

$x^{\frac{1}{3}}-6$

answer blank 4

$x^{\frac{1}{3}}$

3. For f^-1 o f:

$(f^{-1}\circ f)(x)=f^{-1}(f(x))$

Solve

$\begin{gathered} =f^{-1}((x+6)^3) \\ =\sqrt[3]{(x+6)^3}-6 \\ =x+6-6 \\ =x \end{gathered}$

answer blank 5

$(x+6)^3$

answer blank 6

$(x+6)^3$

answer blank 7

$x+6$

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1 year ago

I need help I’m stuck

marysya [2.9K]

Answer:

3rd one

Step-by-step explanation:

i did it

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2 years ago

Please help!!<br><br>x^3+216

Evgen [1.6K]

You can't simplify this equation anymore because they have no like terms.

8 0

3 years ago

Read 2 more answers