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3 years ago

Plzz help science..............

Chemistry

1 answer:

zlopas [31]3 years ago

4 0

Answer:

I would say: D.

Explanation:

["Frequency is the number of times an object vibrates in 1 second; frequency is also measured in hertz and is recognized by your ears as differences in pitch."] Frequency is how many times an object vibrates in ONE second. So that knocks the answer down to either A or B. Frequency itself is also measured in hertz, which knocks the answer to: D. hertz per second.

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The pH of a basic solution is 8.87. What is [H⁺]?

juin [17]

pH be x

$\\ \rm\rightarrowtail -log[H^+]=8.87$

$\\ \rm\rightarrowtail log[H^+]=-8.87$

$\\ \rm\rightarrowtail [H^+]=10^{-8.87}$

$\\ \rm\rightarrowtail [H^+]=1.34$

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2 years ago

Sir J.J. Thompson discovered the electron in 1897. How did Thompson explain the overall neutral charge of the atom?

navik [9.2K]

your answer is C you're welcome

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3 years ago

Jake collected samples of two substances while he was out walking. After taking the samples home, he ran tests and found that on

inysia [295]

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7 0

4 years ago

Read 2 more answers

WILL GIVE BRANLIEST TO FIRST ANSWER!!! I know the correct answer is either a or d. Can anyone explain which one it is and why? C

oee [108]

Answer: The IUPAC name of $CH_3C\equiv CCH_2CH_2Cl$ is 5-chloro-2-pentyne

Explanation:

1. First select the longest possible carbon chain. For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The longest possible carbon chain should contain all the bonds and functional groups.

3. The numbering is done in such a way that the carbon containing the functional group or substituent gets the lowest number. Triple bond is given priority over substituent halogen.

4. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne.

Thus the IUPAC name of $CH_3C\equiv CCH_2CH_2Cl$ is 5-chloro-2-pentyne

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3 years ago

decomposition of hydrogen peroxide produce water and oxygen . calculate the volume of O2 formed from the decomposition of 150 mL

Ugo [173]

Explanation:

2H2O2 => 2H2O + O2

Moles of hydrogen peroxide = 0.150dm³ * (0.02mol/dm³) = 0.003mol .

Moles of oxygen = 0.0015mol.

Volume of oxygen = 0.0015mol * (22.4dm³/mol) = 0.0336dm³.

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3 years ago