Does vb theory indicate that the diatomic molecule he2 is a viable species? rationalize your answer

Chemistry

1 answer:

iragen [17]11 months ago

5 0

VB theory does not indicate that the diatomic molecule He₂ is a viable species.

Helium has atomic number 2, it has 2 protons and 2 electrons.

Electron configuration of helium atom: ₂He 1s².

Helim (He) is a noble gas.

Noble gases (group 18) are in group 18: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe) and radon (Rn). They have very low chemical reactivity.

Noble gases have very stable electron configuration and does not need to gain electrons, only when they gain energy.

Valence bond (VB) theory explains chemical bonding.

Helium atom is stable and does not form molecule.

More about valence bond (VB) theory: brainly.com/question/23129240

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For a beryllium-gold voltaic cell containing Be2+(aq) and Au3+(aq) solutions, do the following. (a) Identify the cathode. (Inclu

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Answer: Gold act as cathode.

Explanation:

Standard potential for an electrochemical cell is given by:

$E^0{cell}$ = standard electrode potential = $E^0{cathode}-E^0{anode}$

The $E^0$ values have to be reduction potentials.

Reduction potentials for given elements

$E^o_{Be^{2+}/Be}=-1.97V$

$E^o_{Au^{3+}/Au}=+1.40V$

The element Be with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

Cathode : $2Au^{3+}+6e^-\rightarrow 2Au$