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Andrej [43]
1 year ago
13

Does vb theory indicate that the diatomic molecule he2 is a viable species? rationalize your answer

Chemistry
1 answer:
iragen [17]1 year ago
5 0

VB theory does not indicate that the diatomic molecule He₂ is a viable species.

Helium has atomic number 2, it has 2 protons and 2 electrons.

Electron configuration of helium atom: ₂He 1s².

Helim (He) is a noble gas.

Noble gases (group 18) are in group 18: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe) and radon (Rn). They have very low chemical reactivity.

Noble gases have very stable electron configuration and does not need to gain electrons, only when they gain energy.

Valence bond (VB) theory explains chemical bonding.

Helium atom is stable and does not form molecule.

More about valence bond (VB) theory: brainly.com/question/23129240

#SPJ4

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En un vaso de precipitado de un litro se coloca exactamente 500 mL de agua destilada a temperatura ambiente y se realizan dos ex
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Answer:

1) La masa del agua a temperatura ambiente es de 500 gramos, 2) La masa del agua cuando se congela es de 500 gramos, 3) La masa de agua que queda después de la evaporación es de 400 gramos, 4) Se ha evaporado 100 gramos de agua.

Explanation:

1) <em>¿Cuál es la masa de agua a temperatura ambiente?</em>

Podemos determinar la masa inicial del agua (m_{o}), medido en gramos, al conocer su densidad (\rho_{w}), medida en gramos por mililitro, y volumen inicial ocupado en el vaso de precipitado (V_{o}), medido en mililitros, a partir de la siguiente expresión:

m_{o} =\rho_{w}\cdot V_{o}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{o} = 500\,mL, entonces:

m_{o} = \left(1\,\frac{g}{mL} \right)\cdot (500\,mL)

m_{o} = 500\,g

La masa del agua a temperatura ambiente es de 500 gramos.

2) <em>¿Cuál es la masa de agua cuando se congela?</em>

Puesto que el proceso de congelación no implica transferencia de masa, la masa de agua se conserva al transformarse en hielo. Por tanto, la masa resultante es de 500 gramos.

3) <em>¿Cuál es la masa de agua que queda después de la evaporación?</em>

Durante la evaporación una parte del agua es transferida al aire, entonces podemos calcular la masa final (m_{f}), medido en gramos, de la sustancia al multiplicar el volumen final (V_{f}), medido en mililitros, por la densidad del agua (\rho_{w}), medida en gramos por mililitro,. Es decir,

m_{f} =\rho_{w}\cdot V_{f}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{f} = 400\,mL, entonces:

m_{f} = \left(1\,\frac{g}{mL} \right)\cdot (400\,mL)

m_{f} = 400\,g

La masa de agua que queda después de la evaporación es de 400 gramos.

4) <em>¿Qué masa de agua se evaporó? </em>

Determinamos que la masa evaporada de agua (m_{v}), medida en gramos, es igual a la diferencia entre las masas inicial y final, ambas medidas en gramos:

m_{v} =m_{o}-m_{f}

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m_{v} = 500\,g -400\,g

m_{v} = 100\,g

Se ha evaporado 100 gramos de agua.

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