Ask question

Ask question

All categories

3 years ago

6

decomposition of hydrogen peroxide produce water and oxygen . calculate the volume of O2 formed from the decomposition of 150 mL

of 0.02M hydrogen peroxide at stp

1 answer:

Ugo [173]3 years ago

5 0

Explanation:

2H2O2 => 2H2O + O2

Moles of hydrogen peroxide = 0.150dm³ * (0.02mol/dm³) = 0.003mol .

Moles of oxygen = 0.0015mol.

Volume of oxygen = 0.0015mol * (22.4dm³/mol) = 0.0336dm³.

You might be interested in

Is there any way to memorize the periodic table of elements in one night with the ionic charges and atomic mass, because if not

kirill [66]

Answer:

Maybe try to memorize it by the valence electrons. You can do this!!

7 0

3 years ago

I need help with number 23

kykrilka [37]

It's asking what are the conditions of the water when the three types of fishes overlap. the three kids of fishes overlap over in the middle which is D. mild temperatures, some suspended particles, flows at medium speed.

8 0

3 years ago

If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength?

kotegsom [21]

Answer:

C I think

Explanation:

I learned this last year

4 0

3 years ago

Read 2 more answers

-1.42, 3, 32.5%, √4, 2³, −0.375, 3/8 as a decimal least to greatest

nignag [31]

Answer:

-1.42, -0.375, 32.5% (.325), 3/8 (.375), √4 (2.0), 3 (3.0), 2³ (8.0)

8 0

1 year ago

When 500.0 g of water is decomposed by electrolysis and the yield of hydrogen is only 75.3%, how much hydrogen chloride can be m

Evgen [1.6K]

The amount of hydrogen chloride that can be made is 1064 g

Why?

The two reactions are:

2H₂O → 2H₂ + O₂ 75.3 % yield

H₂ + Cl₂ → 2HCl 69.8% yield

We have to apply a big conversion factor to go from grams of water (The limiting reactant), to grams of HCl, the final product. We have to be very careful with the coefficients and percentage yields!

$500.0gH_2O*\frac{1moleH_2O}{18.01 gH_2O}*\frac{2 moles H_2}{2 moles H_2O}*\frac{2.015g H_2}{1 mole H_2}*\frac{75.3 actual g}{100 theoretical g}=42.12 g H_2$

$42.12H_2*\frac{1 mole H_2}{2.015gH_2}*\frac{2 moles HCl}{1 mole H_2}*\frac{36.46g}{1 mole HCl}*\frac{69.8 actualg}{100 theoreticalg} =1064gHCl$

Have a nice day!

#LearnwithBrainly

7 0

4 years ago