Answer:
Oceanic trenches
Explanation:
Oceanic Trenches are hemispheric-scale long but narrow topographic depressions of the sea floor
Answer:-
Chlorine gas is passed through a solution of flower to
<u>decolourise the flower</u>
<u></u>
Explanation:
Chlorine is used as a bleaching agent because of its oxidising nature.
This nascent "O" is highly reactive in nature and bleaches the substance that comes into its contact.
when flowers are passed through the chlorine solution , it oxidises the solution and removes the colour from the flower.
This property also made its use as water-disinfectant reagent.
Chlorination is done to make the water useful for drinking
It kills the harmful bacteria present in the water.
Answer:
144g of H₂O
Explanation:
3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)
From the equation:
3 moles of NH₄ClO₄ produced 6 moles of H₂O
4 moles of NH₄ClO₄ produced ? moles of H₂O
(4 ₓ 6)/3 = = 8 moles of H₂O
1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)
8 moles of H₂O = ?
Therefore 8 × 18 = 144g
=144g of H₂O
In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
given that :
The solute in the solution by mass percent = 10 %
mass percent = ( mass of solute / mass of solution ) × 100%
mass of solute in the solution is = 10 g
The solvent present in solution by mass percent = 90 %
the mass of solvent in the solution is is 90 g
Thus, In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
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Answer: The value of for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.
Its solubility product will be as follows.
Cell reaction for this equation is as follows.
Reduction half-reaction: ,
Oxidation half-reaction: , = ?
Cell reaction:
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product,
=
Therefore, according to the Nernst equation
At equilibrium, = 0.00 V
Putting the given values into the above formula as follows.
=
= 0.577 V
Hence, we will calculate the standard cell potential as follows.
= 0.222 V
Thus, we can conclude that value of for the half-cell reaction is 0.222 V.