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Yuki888 [10]
3 years ago
14

Luis bought a box of 84 nails.He used 3/4 the nails in the box.How many nails did he use?

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0
Answer: 63

Step By Step: Put 84 over a 1 to make this easier. One in the format, multiply 84/1 by 3/4. You should get 252/4. One you simply this you should get 63.
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Danika has one apple that weighs 1/4 lb and another apple weighs 3/16 lb. Find the DIFFERENCE in their weights.
Mama L [17]

Answer: A.

Step-by-step explanation:

Danika has 1/4 lb apple and a 3/16 apple. We have to find a common denominator to be able to subtract them. We can do this by finding out 4 times how much equals 16. Which is 4. So you multiply both of the numbers by 4, (1x4 = 4 , 4x4 = 16) being 4/16. Now you just have to subtract the top numbers "4-3 = 1" 1/16.

4 0
3 years ago
Read 2 more answers
What is 15 didvide 7.35
zvonat [6]

Answer:

2.04081632653

Step-by-step explanation:

If you wanted to round it, it would be 2 because the 4 isn't enough to bump it up. Hope this helped you!

4 0
3 years ago
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An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
For what value of x does 84^3x=512^2x+12
stealth61 [152]

2.193 X 10^-5

this is the answer

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3 years ago
04.03PLS HURRY PLSS ALL MY POINTS AND BRAINLESS
Whitepunk [10]
B because 120+ 40x equals the subtopic of the route of
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1 year ago
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