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3 years ago

Please help!

Mathematics

2 answers:

Papessa [141]3 years ago

6 0

Answer:

x = 1 and x = 2

x = 4 and x = -4

Step-by-step explanation:

Vertical asymptotes appear where the function does not have a value. This is most commonly when the denominator of a rational function is 0. Find the asymptotes by factoring the denominator and setting it equal to 0. Then solve for x.

<u>First equation</u>

x² - 3x + 2 factors into (x-1)(x-2)

When x-1 = 0, x = 1. When x-2=0, x = 2. The V.A. are at x = 1 and x = 2.

<u>Second equation</u>

x² - 16 factors into (x+4)(x-4)

When x+4= 0, x = -4. When x-4 = 0, then x = 4. The V.A. are at x = -4 and x = 4.

Amanda [17]3 years ago

3 0

B. x = -4

C. x = 4

Edgenuit.y2020 dudets

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RoseWind [281]

Answer:

Cost of each ticket bought by Peter = $8 for each ticket

Step-by-step explanation:

Given:

Number of ticket bought by Peter = 9 tickets

Amount paid by Peter for tickets = $72

Find:

Cost of each ticket bought by Peter

Computation:

Cost of each ticket bought by Peter = Amount paid by Peter for tickets / Number of ticket bought by Peter

Cost of each ticket bought by Peter = 72 / 9

Cost of each ticket bought by Peter = $8 for each ticket

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2 years ago

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2 years ago

Find the average rate of change for the function f(x)=3.2 + 25

wel

The average rate of change of the function is: 3.2.

<h3>What is the Average Rate of Change for a Function?</h3>

Average rate of change = $\frac{f(b) - f(a)}{b - a}$

Given the function, $f(x) = 3.2x + 25$ , the average rate of change over the interval of x = 2 to x = 6 would be calculated as shown below:

a = 2

b = 6

f(a) = f(2) = 3.2(2) + 25 = 31.4

f(b) = f(6) = 3.2(6) + 25 = 44.2

Average rate of change = (44.2 - 31.4)/(6 - 2) = 3.2.

Learn more about average rate of change on:

brainly.com/question/11627203

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2 years ago

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nydimaria [60]

Answer:

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Step-by-step explanation:

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2 years ago

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu

Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

Traditional Accelerated Total

Math-pathway Math-pathway

Female 1244 116 1360

Male 1054 54 1108

Total 2298 170 2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

$P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)$

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

$P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}$

If the two events are independent then:

P (F|A) = P(F)

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0

2 years ago