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Ahat [919]
2 years ago
12

What is the sum of three fours and four threes

Mathematics
2 answers:
Oduvanchick [21]2 years ago
7 0
The.   Answer  is. 145.  Because.  If you multiply 3 x3x3x3 which equals 81. And  add 4x4x4 which equals 64. Will give you the sum of 145.
Bumek [7]2 years ago
7 0
Three 4's = 12
Four 3's = 12
Sum of the two = 24
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Active ingredient of a pill comprises 45% of the pill mass. If a pill contains 325 mg of active ingredient,
uranmaximum [27]

Answer:

Step-by-step explanation:

The idea here is to be able to write and then solve the equation needed for this. In words, this is what you are looking to solve: "The active ingredinet is 45% of the mass of the pill". Putting those words into an equation:

active ingredient = .45 (mass of pill). Since our active ingredient is 35 mg:

325 = .45m and divide by .45:

m = 722.2 mg

6 0
3 years ago
Trigonometry heeellllppp plzzzz​
algol [13]

Answer:

x ≈ 3.4 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin57° = \frac{opposite}{hypotenuse} = \frac{x}{4} ( multiply both sides by 4 )

4 × sin57° = x , thus

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3 0
3 years ago
Multiply: (3x – 5)(–x + 4)
LiRa [457]

Answer:

Step-by-step explanation:

(3x – 5)(–x + 4)

(3x)(–x) + (3x)(4) + (–5)(–x) + (–5)(4).

-3x^2+12x +5x -20

-3x^2+ 17x -20

4 0
3 years ago
Read 2 more answers
1. (-78) + (-98) =
Iteru [2.4K]

Answer:

1.-179

2.68

3. 11

4. 25

5. -734

8 0
2 years ago
Solve:
STatiana [176]

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

The given equation is:

3-k=\sqrt{3k+1}

Square both sides of the equation

(3-k)^2=3k+1

Expand the left side of the equation above

(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1

Write the quadratic equation in standard form

k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\

Factor the quadratic equation

(k-8)(k-1)=0

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

Learn more here: brainly.com/question/25840704

8 0
2 years ago
Read 2 more answers
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