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Ahat [919]
3 years ago
12

What is the sum of three fours and four threes

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0
The.   Answer  is. 145.  Because.  If you multiply 3 x3x3x3 which equals 81. And  add 4x4x4 which equals 64. Will give you the sum of 145.
Bumek [7]3 years ago
7 0
Three 4's = 12
Four 3's = 12
Sum of the two = 24
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Given that these simultaneous equations
Tatiana [17]

The value of k is(3\sqrt{ 10})/2

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= \sqrt{15-2x^2}...........(eq iii)

Substitute the value of y into eq i

x-(\sqrt{15-2x^2}= k

x- (\sqrt{15} - 2x= k

k= (3\sqrt{ 10})/2

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0
2 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
Read 2 more answers
2 dots plots with number lines going from 0 to 10. Plot A has 0 dots above 0, 1, and 2, 1 above 3, 2 above 4, 2 above 5, 2 above
alexandr402 [8]

Answer:

First one:

Both the mean and median are greater for Plot A than for Plot B

Step-by-step explanation:

Set A:

Mean:

[1×10 + 2×7 + 2×6 + 2×5 + 2×4 + 1×3]/10

= 5.7

Median:

Median position: (10+1)/2 = 5.5th value

(5+6)/2

Median = 5.5

Set B:

Mean:

[1×7 + 3×6 + 3×5 + 2×4 + 1×3]/10

= 5.1

Median:

Median position: (10+1)/2 = 5.5th value

(5+5)/2

Median = 5

Mean: A is greater

Median: A is greater

8 0
3 years ago
Whats 56753 ÷ 43 = ????????????????????????????????????????????
dalvyx [7]

Answer:

1,319.83721

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
can someone help me solve this multiplying polynomial question? it would really help, the screenshot is attached (:
Korvikt [17]

Answer:

-20x³ + 0x² + 15x - 20

Step-by-step explanation:

I would have said it the other way.

"Multiply each term in the top row by -5."

 4x³ +  0x   -  3x +  4

<u>×(-5</u>)  <u>×(-5</u>)  <u>×(-5)</u>  <u>×(-5) </u>

-20x³ + 0x² + 15x -20

3 0
3 years ago
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