Answer:
y = (C-Ax) /B and x = (C-By)/A
Step-by-step explanation:
y
By = C-Ax
y = (C-Ax)/B
x
Ax = C-By
x = (C-By)/A
To factor x^2 + 2x - 8 follow these steps
1) Write to factors, with x as the first term, this way:
(x )(x )
2) The sign to the right of the x in the first factor is the same sign of the coeficient of x in the polynomial.
That is +.
The sign to the right of the x of the second factor is the product of the sign of the coefficent of x (this is +) and the sign of the independent term (this is - ).
So that is (+).(-) + -.
Now the two factors have this form:
(x + ) (x - )
3) Now find two numbers whose product is - 8 and whose difference is +2
Those numbers are + 4 and -2.
Then the two factors are:
(x + 4) (x - 2).
So the answer if that the correct factorization is (x + 4) (x - 2)
![\sqrt{x} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20)