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3 years ago

9

Mr. Young has a section of his parking lot, measuring 10 yards by 12 yards, that needs to be replaced. The paving company told M

e. Young the workers complete 3 and 1/5 square yards every 1/4 hour. How long should it take to pave the parking lot?

1 answer:

Evgesh-ka [11]3 years ago

7 0

Answer:

36.9230769231

Step-by-step explanation:

10*12

ans/3.25

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If cosθ=2/3 find cscθ using identities. This is in quad. 1.

laiz [17]

Step-by-step explanation:

cos θ = 2/3

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Hence, base = 2 units and hypotenuse = 3 units.

$\quad \twoheadrightarrow\sf { H^2 = B^2 + P^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = H^2 - B^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = (3)^2 - (2)^2} \\$

$\quad \twoheadrightarrow\sf { P^2 = 9- 4} \\$

$\quad \twoheadrightarrow\bf { P = \sqrt{5}} \\$

Now, we know that :

$\quad \twoheadrightarrow\sf {cosec \; \theta = \dfrac{Hypotenuse}{Perpendicular} } \\$

$\quad \twoheadrightarrow\bf{cosec \; \theta = \dfrac{3}{\sqrt{5}} } \\$

Therefore, the required answer is 3/√5.

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2 years ago

Siri am I a mix of recipe that calls for 1 1/2 cups of flour and 3/4 to get butter Jeremiah uses three sticks of butter how many

Inga [223]

Answer:

6 cups

Step-by-step explanation:

jeremiah 4× the recipe

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3 years ago

Find the measures of the following angles.

makvit [3.9K]

Answer:

1: 36° 2: 122° 3: 122° 4: 38°

Step-by-step explanation:

First start out by getting 2 and 3. so 58+angle 3 has to sum to 180° since they are supplementary and are a straight line. So 180-58=122. Angle 2 is the same since theyre vertical. then since a triangle has 180° total, you subtract from 180 to find the final angle measurement.

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Rudiy27

Answer:

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Step-by-step explanation:

Perhaps your equation is ...

f(t) = N·e^(-0.2174t)

We want f(6) = 4, so ...

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N = 4/0.2713 = 14.7 . . . . milligrams

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3 years ago

use the rational zeros theorem to write a list of all potential rational zeros. f(x) = x^3 - 10x^2 4x - 24

Sloan [31]

$f(x) = x^3 - 10x^2 4x - 24 \\\\24:\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm8;\ \pm12;\ \pm24\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm8;\ \pm12;\ \pm24\}}$

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