FfsgdhjwvahavHsvsnksnshsnvbsvsvns
Answer:
A=lw+l(w
2)2+h2+w(l
2)2+h2
Step-by-step explanation:
Answer:
<u>2y - 5 (read below)</u>
Step-by-step explanation:
-8y + 10y = 2y
2 + (-7) = -5
Your expression could/would be:
2y - 5.
Hope this helps!
A function is a rule that assigns exactly one output to a given input. The input is taken from a set called the domain, and the corresponding output belongs to a set called the range.
1. In this exercise, we're calling the pool of patients 1-8 the domain, and the pool of nurses A-D the range. The given table describes a function because any patient is assigned to only one nurse.
2. This wouldn't be a function if at least one patient was assigned to more than one nurse. If this were to happen in practice, the patient could be, say, given the same dose of some medicine twice if the nurses aren't careful.
3. Making the nurse pool the domain and the patient pool the range would give a relation that is not a function, since more than one patient is assigned to one nurse.
7]
6/(x-1)-5x/4
subtracting the above we put the fraction under the same denominator:
6/(x-1)-5x/4
multiplying the denominators we get:
4(x-1)
thus subtracting we get:
6/(x-1)-5x/4
=(4*6-5x(x-1))/[4(x-1)]
=[24-5x^2+5x]/(4x-4)
Answer:
(-5x^2+5x+24)/(4x-4)
9]
3/(x+7)+4/(x-8)
the common denominator is:
(x+7)*(x-8)=(x+7)(x-8)
thus adding the fractions we put them under the same denominator as follows:
[3(x-8)+4(x+7)]/[(x+7)(x-8)]
=[3x-24+4x+28]/[(x+7)(x-8)]
=(7x+4)/[(x+7)(x-8)]
