Help would be appreciated :)

Mathematics

1 answer:

Orlov [11]3 years ago

8 0

Answer:

3y-x=-18

Step-by-step explanation:

3y-x=-18

3y=x-18

y=1/3x-6

Parallel lines have the same slope

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Which equation represents the circle described?

faust18 [17]

ANSWER

${(x - 4)}^{2} + {(y - 3)}^{2} = {2}^{2}$

EXPLANATION

The equation of the circle with radius r and centre (a,b) is given by

$(x - a)^{2} + {(x - b)}^{2} = {r}^{2}$

The radius is

$r = 2$

We need to determine the center of the circle from the given equation of another circle, which is,

${x}^{2} + {y}^{2} - 8x - 6y + 24 = 0$

We complete the square to obtain,

${x}^{2} - 8x+ {y}^{2} - 6y + 24 = 0$

${x}^{2} - 8x+ {y}^{2} - 6y = - 24$
${x}^{2} - 8x+ {( - 4)}^{2} + {y}^{2} - 6y + {( - 3)}^{2} = - 24 + {( - 3)}^{2} + {( - 4)}^{2}$

${(x - 4)}^{2} + {(y - 3)}^{2} = - 24 + 9+ 16$

${(x - 4)}^{2} + {(y - 3)}^{2} = 1$

The centre of this circle is (4,3)

Hence the center of the circle whose equation we want to find is also (4,3).

With this center and radius 2, the required equation is,

${(x - 4)}^{2} + {(y - 3)}^{2} = {2}^{2}$

Therefore the correct answer is C.

3 0

3 years ago

Read 2 more answers

Solve the system of equations using elimination 2x+y=3 and 3x-y=12

Eddi Din [679]

2x + y = 3
3x - y = 12
Add both equations
5x = 15, x = 3
2(3) + y = 3
6 + y = 3, y = -3
Solution: x = 3, y = -3... or (3,-3)

3 0

3 years ago

I'm so confused and need help

siniylev [52]

Answer:

SAS, SSS, AAA