Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58
Answer:
finding the number of equal-sized parts into which a number can be split
Step-by-step explanation:
Let us split the number 80 into 10 equal parts.
80 = 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8
= 8 + 8 + 8 +...to 10 times
= 8(10)
or 
So, if N is any number and p is one of its equal part, then the number of parts into which N is split by p is
.
Hence, finding the number of equal-sized parts is best modeled with a division expression.
Answer:

Step-by-step explanation:
1) Use square sum: (a + b)² = a² + 2ab + b².

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>2xy</u><u> </u><u>+</u><u> </u><u>y</u><u>²</u>.
Answer:
c 364
Step-by-step explanation:
this is the correct answer because the rest are lower answers