Angle θ is in standard position. if sin(θ) = − 1/3, and π < θ < 3π/2 , find cos(θ).
2 answers:
Answer:
-2√2/3 is the correct answer. :))
Step-by-step explanation:
Use pythagorean theorem: sin^2 + cos^2 = 1 (-1/3)^2 + cos^2 = 1 1/9 + cos^2 = 1 cos^2 = 8/9 cos = +- sqrt(8)/sqrt(9) = +- 2sqrt(2)/3 Determine whether cos is positive or negative by looking at which quadrant the angle is in. pi < theta < 3pi/2 ---> this is 3rd quadrant where x or cos is negative Therefore cos(theta) = -2sqrt(2)/3
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