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3 years ago

How manet times dose 50 go into 1,000

Mathematics

2 answers:

strojnjashka [21]3 years ago

6 0

Answer:

20 times

Step-by-step explanation:

1,000 divided by 50 will be 20 try using lone division :)

Gnoma [55]3 years ago

3 0

Answer:

20 times

Step-by-step explanat

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Find the<br>degree of the algebraic<br>expression:<br>3x^3 + 3x^2y^2 - y^2

Ghella [55]

Answer:

Degree 4

Step-by-step explanation:

Expression:

3x^3 + 3x^2y^2 - y^2

3x^3 - degree 3
3x^2y^2 - degree 2+2 = 4
y^2 - degree 2

So the expression has degree 4 as per the highest degree of the terms

4 0

3 years ago

5,-15,35,55....<br> What is the common difference

harkovskaia [24]

Answer:

The common difference is -20

Step-by-step explanation:

Simply subtract 5 from -15

-15-5 = -20

3 0

3 years ago

Read 2 more answers

How to do 10 to 4 decrease

USPshnik [31]

If you're talking about the ratio 10:4, you can decrease it by dividing both numbers by 2.

10:4=5:2

The ratio decreases to 5:2

6 0

3 years ago

Read 2 more answers

Mapiya writes a series of novels. She earned \$75{,}000$75,000dollar sign, 75, comma, 000 for the first book, and her cumulative

qwelly [4]

Answer:

$E(n)=75000 \times 2^n$

Complete question:

write a function that gives mapiyas cumulative earnings E(n), in dollars when she has written n sequel's

Step-by-step explanation:

According to the question, she earned $75000 for the first book.

Also,We are given that her cumulative earnings double with each sequel that she writes.

Assuming she has written n sequel's

Now since we are given that her cumulative earnings double with each sequel

So, her initial earning will be $2^n$ times

So, her earning will be : $75000 \times 2^n$

Now we are given that cumulative earnings is denoted by E(n)

So, the function becomes : $E(n)=75000 \times 2^n$

Hence a function that gives Mapiya's cumulative earnings E(n), in dollars when she has written n sequel's is $E(n)=75000 \times 2^n$

4 0

3 years ago

Pine Lane Middle School's student council has 10 seventh graders and 8 eighth graders serving as representatives. A subcommittee

Nikitich [7]

Hey there! I'm happy to help!

When dealing with picking things and finding the number of possibilities, we can be dealing with two different types of things: permutations or combinations. We use permutations when order is important to the groups and we use combinations if order is not important.

It appears here that order is not important here as the subcommittee doesn't have to be in a specific order, so we will be using combinations.

So, we have ten seventh graders to choose from. Then we will have 9, and then 8. So, we multiply these numbers of choices.

10×9×8=720

Now, we need to divide by 6. This is to show that order doesn't matter. Why? Because there are 6 possible ways to organize 3 seats on the committee (3×2×1), and we want to divide out all of the different orders so it is just the specific group of people and not their different organizations that are counted.

720/6=120

Now, we need to find this with the eighth graders.

8×7×6=336

And we divide by the number of seats factorial (3 seats for the eighth graders, so 3×2×1=6 again)

336/6=56

Now, we multiply our numbers for seventh and eighth graders to find all off the possibilities.

120×56=6720

So, there are 6720 subcommittees possible.

Have a wonderful day and keep on learning! :D

6 0

3 years ago