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NISA [10]
3 years ago
6

12x=3 Already forgot

Mathematics
2 answers:
Kamila [148]3 years ago
6 0

Answer:

it is x= 1/4

Step-by-step explanation:

12x=3

12x : 12= 3 : 12

X= 3/12

x= 1/4

egoroff_w [7]3 years ago
4 0

The answer is x=\frac{1}{4}

First, you must divide 12 on both sides.

x=\frac{3}{12}

Then, simplify the fraction.

x=\frac{1}{4}

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Please help me if you can. Please also write how you got the answer thank you.
babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

<em />

For question 10, it states \frac{1}{4}. This can be split into \frac{3}{x} and \frac{3}{x} . When x is 12 in the first equation then \frac{3}{12} = \frac{1}{4} and when x is 6 in the second equation \frac{3}{6} =0.5 (0.5 is also  \frac{1}{2}). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11  or  5 whole numbers.

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3 years ago
Pls help ur girl out with math
Zinaida [17]
135 degrees is your answer
8 0
3 years ago
1. Tracy has a photo album with 5 pages. Each
natka813 [3]

Answer:

20 photos

Step-by-step explanation:

4 photos per page, 5 pages. 4 x 5 is 20.

5 0
3 years ago
Read 2 more answers
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
What is the correct answer for evaluate the expression 12 to 2nd power​
Leya [2.2K]

Answer:

144

Step-by-step explanation:

3 0
3 years ago
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