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OLEGan [10]
3 years ago
6

According to some students, What's is the true purpose of homework? 19 letters page 156 Algebra 1 worksheet

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

(wouldn't this be English?)
The true purpose of homework to me is to learn more and to help you remember what you have learned.
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What is the slope of the line?<br> y + 5 = 2(x + 1)<br><br> A. 1/5<br> B. 2/5<br> C. 2<br> D. 1/2
Zinaida [17]

Answer:

it's 2

Step-by-step explanation:

hope this helps you.

7 0
3 years ago
Read 2 more answers
From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
Will’s bowling average after 5 games was 120. In his next 3 games,Will scored 118, 124, and 142. What was Will’s bowling average
Irina-Kira [14]
His new average is 123.
3 0
3 years ago
How much carbon dioxide is produced from running a microwave (1500 watts) for 10 minutes per day for one month? (round to the te
svetlana [45]

Answer: 10.3 pounds of CO2 is produced

Step-by-step explanation:

Assuming there are 30 days in a month, if the microwave is run for 10 minutes per day, then the number of minutes for which the microwave is run in a month is

30 × 10 = 300 minutes

We would convert from minutes to hours

60 minutes = 1 hour

Therefore,

300 minutes = 300/60 = 5 hours

Also,

1000 watts = 1 kW

Therefore,

1500 watts = 1500/100 = 1.5kw

Therefore, the number of kWh is

1.5 × 5 = 7.5 kWh

If 1.37 pounds CO2 per kWh, then

If 1kWh = 1.37 pounds CO2, then

7.5 kWh = 7.5 × 1.37 = 10.3 pounds rounded to the nearest tenth

8 0
4 years ago
The length of a rectangular garden is 5 meters more than its width. If the
IRINA_888 [86]

Answer:

Width of rectangular garden = 10 meter

Step-by-step explanation:

Given;

Area of rectangle garden = 150 m²

Length of rectangular garden = 5 meters more than its width

Find:

Width of rectangular garden

Computation:

Assume;

Width of rectangular garden = W

So,

Length of rectangular garden = 5 + W

Area of rectangle garden = length x width

(W)(W + 5) = 150

W² + 5W = 150

W² + 5W - 150 = 0

W² + 15W - 10W  - 150 = 0

W(W + 15) - 10(W + 15) = 0

(W + 15)(W - 10)

So,

W = -15, W = 10

Width of rectangular garden = 10 meter

8 0
3 years ago
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