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Mariulka [41]
2 years ago
8

A stadium has 53,000 seats. Seats sell for ?$42 in Section? A, ?$36 in Section? B, and ?$30 in Section C. The number of seats in

Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ?$1,995,000 from each? sold-out event. How many seats does each section? hold?
Mathematics
1 answer:
Vlada [557]2 years ago
3 0
Section A holds 27,000 seats, Section B holds 14,200 seats, and Section C holds 12,800 seats
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The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle​
AVprozaik [17]

Answer:

  • Length of rectangle is 31 yards and Width is 24 yards.

Given:

  • The length of a rectangle is 7 more than the width.
  • The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

\\  \:  \:  \:  \:  \pink{ \dashrightarrow \:  \:  \:  \:  \sf { \underbrace{Area_{(Rectangle)} =  Length × Width  }}} \\  \\

On Substituting the required values, we get;

\\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x - 744 = 0 \\ \\ \\  \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x = 24 \:  or \:   - 31 \\ \\

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

  • Width of rectangle = x = 24 yards
  • Length of the rectangle = x + 7 = 31 yards

\thereforeLength of rectangle is 31 yards<u> </u>and Width is 24 yards.

8 0
2 years ago
A company has two large computers. The slower computer can send all the company's email in 35 minutes. The faster computer can c
Naddik [55]

The rate for the first is 1 job / 35 minutes and for the second is 1 job / 15 minutes.  So combined we get

r = 1/35 + 1/15

3×5×7r = 3 + 7 = 10

r = 10/(105) jobs per minute

We're interested in 1/r

1/r = 105/10 = 10.5 minutes per job

Answer: 10.5 minutes

4 0
2 years ago
Solve 2(x + 1) = 2x + 5.​
algol13
Answer—> no solution
3 0
3 years ago
Read 2 more answers
At noon a train leaves Washington, D.C., headed for Charleston, South Carolina, a distance of 500 mi. The train travels at a spe
Bogdan [553]

Answer:

6 hours

Step-by-step explanation:

Answer:

6 hours

Step-by-step explanation:

Firstly, it is important to know where the train that leaves Washington will get after one hour since they didn't start at the same time between noon and 1 is 1 hour.

Speed = distance / time

Distance = speed * time

The distance S = 44 * 1

S= 44m

To determine the time they will pass each other

500(total distance)- 44 ( distance gotten to in 1 hour) - d(the distance it willl pass each other =44* t(time the train will pass each other.

456-d =44t

Second train

d = 32t

Substituting to the equation

456-32t=44t

456=76t

t= 6 hours.

The time they will pass each other is six hours.

4 0
3 years ago
Answers needed as soon as possible
Naily [24]
Basically the answer is 6, if you'd like an explanation, let me know. :)
6 0
3 years ago
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