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yulyashka [42]
3 years ago
9

Evaluate the imaginary number i^3

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
The answer to the problem i^3 is -i
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Answer the following question.
Ivenika [448]

Answer:

6

Step-by-step explanation:

Step 1: equal any two of the three equations together

2x + 3 = 3x - 9

Step 2: isolate the variable

3 = x - 9

6 = x

5 0
3 years ago
Read 2 more answers
Evaluate the given question
Natali5045456 [20]

The value of the given expression is 1/16

<h3>Exponential functions</h3>

Given the exponential function below as shown;

(1/2)^4

This means the product of 1/2 in 4 places. This can be expressed as;

(1/2)^4 = 1/2 * 1/2 * 1/2 *1/2

(1/2)^4 = 1/4 * 1/4

(1/2)^4 =1/16

Hence the value of the given expression is 1/16

Learn more on exponent here: brainly.com/question/725335

#SPJ1

5 0
1 year ago
Candace said I'm thinking of a fraction. If I divide it by 1/2,I get 3/11.what fraction was Candace thinking of??
Pavlova-9 [17]
Multiply back by 1/2, to get 3/22.
6 0
3 years ago
Read 2 more answers
I need help please????
mezya [45]

Answer:

112

Step-by-step explanation:

Just solve it easy peasy

7[(25+9)-3(2-1)]

First solve the inner brackets

7[(34)-3(3)]\\7[25-9]

Now the other brackets

7[25-9]\\7[16]\\112

5 0
3 years ago
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Need help with linear approximation
Dmitrij [34]
Consider a function f(x), the linear approximation L(x) of f(x) is given by

L(x)=f(a)+(x-a)f'(a)

Given the quantity: \frac{1}{203}

We approximate the quantity using the function f(x)= \frac{1}{x}, where x = 203.

We choose a = 200, thus the linear approximation is given as follows:

L(203)=f(200)+(203-200)f'(200) \\  \\ = \frac{1}{200} - \frac{3}{200^2} = \frac{200-3}{200^2} = \frac{197}{40,000} =0.004925
5 0
3 years ago
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