The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100
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An equation is an expression used to show the relationship between two or more variables or numbers.
The magnitude of the second atom relative to the first = magnitude of second atom / magnitude of first atom
The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100
Find out more on Equation at: brainly.com/question/13763238
What is it?
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
How do you find IQR?
<em>Step 1: Put the numbers in order. ...</em>
<em>Step 2: Find the median. ...</em>
<em>Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...</em>
<em>Step 4: Find Q1 and Q3. ...</em>
<em>Step 5: Subtract Q1 from Q3 to find the interquartile range.</em>
V = s³. Therefore, s = ³√ V
Hope that helps you
The are 4 different possibilities to draw a ten, namely a ten of the four different suits. The probability of the event is the ratio of the 4 possibilities and the total number of possible choices, whcih is 52:
P(E) = 4/52 = 1/13 or about 7.7%
Answer:
The graph crosses the x axis at x=0. For x> 0, it rises to a maximum value and then decreases toward y= 0 as x goes to infinity. For x< 0, it decreases to a minimum values then rises toward y= 0 as x goes to negative infinity. y= 0 is a horizontal asymptote but the graph crosses y= 0 at x= 0.
Step-by-step explanation:
A common mistake that students make is to think that a graph cannot cross a slant or horizontal asymptote. This is not the case! A graph CAN cross slant and horizontal asymptotes (sometimes more than once). It's those vertical asymptote critters that a graph cannot cross.
