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2 years ago

48. A wire is securely attached from the top of

Mathematics

1 answer:

hodyreva [135]2 years ago

6 0

Answer:

D. 29.5 feet

Step-by-step explanation:

1) First you use the pythagorean theorem a^2+b^2=c^2

2) 26^2+14^2=c^2 The wire is the hypotenuse.

3) Simplify the equation. 676+196=c

4) 872=c

5) Find the square root of 872 and round to the nearest tenth.

6) Your answer is 29.5 feet.

Hope this helps!

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Homework #16- Complete all odd questions.

katen-ka-za [31]

Question 1)

Given

The expression is 5xy

To determine

Find the value of 5xy if x = 2 and y = 3

5xy

substitute x = 2 and y = 3

5xy = 5(2)(3)

= 5(6)

= 30

Therefore, the value of 5xy = 30 if x = 2 and y = 3.

Note: your remaining questions are not mentioned. But, the procedure may remain the same. Hopefully, your concept will be cleared anyway.

8 0

2 years ago

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

3 years ago

Use the given graph to determine the limit, if it exists.

Georgia [21]

The limit is - 1.
_____

5 0

3 years ago

Read 2 more answers

1. Triangle STU with vertices S(-4, 2) T(5, -1),

Alexus [3.1K]

Answer:

S’ (-5,-3)

T’ (4,-6)

U’ (-3,-7)

Step-by-step explanation:

Basically, we want to apply the given transformation rule of the axes to get the coordinates of the images

The rule is that we subtract 1 from the x-coordinates and also subtract 5 from the y-coordinates

Thus, we proceed as follows;

S’ = (-4-1, 2-5) = (-5,-3)

T’ = (5-1, -1-5) = (4,-6)

U’ = (-2-1,-2-5) = (-3,-7)

4 0

2 years ago

Which has the greater area: a 6 6‐centimeter by 4 1 2 412‐centimeter rectangle or a square with a side that measures 5 5 centime

Morgarella [4.7K]

Answer:

The square with side 5 centimeters have a greater area.

Corrected question;

Which has the greater area: a 6‐centimeter by 4.12‐centimeter rectangle or a square with a side that measures 5 centimeters?

Step-by-step explanation:

The Area of a rectangle can be written as;

Area A = length × breadth

Given;

Length = 6 cm

Breadth = 4.12 cm

Substituting the values;

Area of rectangle = 6cm × 4.12cm = 24.72 cm^2

For the square;

Area of a square = length × length

Given;

Length = 5 cm

Substituting the values;

Area of the square = 5cm × 5cm = 25 cm^2

Since 25 cm^2 is greater than 24.72 cm^2

The square has a greater area.

4 0

3 years ago