Question

Compute the value of the discriminant and give the number of real solutions of the quadratic equation. 4x^2-7x+2=0

Answer 1

Answer:

Discriminant is 17 and it has 2 real roots.

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

• $b^2-4ac>0$ yields 2 real roots

• $b^2-4ac=0$ yields 1 real root

• [tx]b^2-4ac<0[/tex] yields no real roots

$4x^2-7x+2=0$ where a=4, b=-7, and c=2

$b^2-4ac=(-7)^2-4(4)(2)=49-32=17$.

It has 2 real roots