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labwork [276]
3 years ago
5

Which interval for the graphed function contains the local maximum?

Mathematics
2 answers:
Maksim231197 [3]3 years ago
6 0

The local maximum is the bump around x=1.4 so

Answer: [1,2]


sertanlavr [38]3 years ago
5 0

Answer:

Step-by-step explanation:

B) [1,2]

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Hi can someone check my answers please? thanks, :).
gregori [183]
The 3rd answer is wrong, the answer is 19.
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The 7th answer is wrong, the answer is 8.
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5 0
2 years ago
Read 2 more answers
Please help me IDK how to do this!!!!!!
tatiyna
A parallelogram should have 2 sets of parallel lines. Let's find the slope of line PQ and RS to test.

PQ:
(4-2)/(1-(-3))
2/4
1/2

RS:
(2-0)/(3-1)
2/2
1

Because 1 does not equal 1/2 (the slopes are different) the lines are not parallel. Thus, the figure is not a parallelogram.
5 0
2 years ago
Your firm has a contract to make staff uniforms for a fast-food retailer. The heights of the staff are normally distributed with
FromTheMoon [43]

Answer:

a) 16%

b) 2.5%

Step-by-step explanation:

a)

The mean is 70 with standard deviation(SD) of 3 and you are asked to find out the percentage of staff that have <67(70-3 inch= mean - 1 SD) inch size, which means 1 SD below the mean (<-1 SD). Using 68-95-99.7 rule, you can know that 68% of the population is inside 1 SD range from the mean ( -1 SD to + 1 SD).

To put it on another perspective, there are 32% of the population that have < -1 SD and > +1 SD value. Assuming the distribution is symmetrical, then the value of < - 1 SD alone is 32%/2= 16%

b)

The question asks how many populations have size >76 inches, or mean + 2 SD (70+3*2 inch).

You can also solve this using 68-95-99.7 rule, but you take 95% value as the question asking for 2 SD instead.  Since 95% of population is inside 2 SD range from the mean ( -2 SD to + 2 SD), so there are 5% of population that have < -2 SD and > +2 SD value. Assuming the distribution is symmetrical, then the value of > +2 SD alone is 5%/2= 2.5%

3 0
2 years ago
In circle O below, AB is a diameter and m
Neko [114]

Answer:

i don't know

Step-by-step explanation:

i seriously don't know

4 0
2 years ago
If a tree 41.8 feet tall casts a shadow that is 27 feet long, find the height of a tree casting a shadow that is 18.3 feet long
Neko [114]

Answer:

28.3 feet

Step-by-step explanation:

Given a tree 41.8 feet tall casts a shadow that is 27 feet long

So the Tangent of the angle of the sahdow remains the same for the both trees.

We know that  Tanx=\frac{height of the tree}{length of the shadow}

\frac{height of the tree1}{length of the shadow1} = \frac{height of the tree2}{length of the shadow2}

\frac{41.8}{27} =\frac{x}{18.3}

x=\frac{41.8}{27}\times18.3 =28.3

Therefore the height of the tree is 28.3 feet

6 0
3 years ago
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