Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)
1 answer:
f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
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Hope this helps!
If not, I am sorry.
3c^3. This is probably it. I'm pretty positive.