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Sedbober [7]
3 years ago
13

Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) =   3(x -2)^2   This = 0 at the turning points:-

so 3(x - 2)^2 =  

giving x = 2 .  When x = 2     f(x)  =  3(2-2)^3 + 1 = 1

Answer is (2, 1)


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