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3 years ago

Complete the following equation using <, >, or = 120% ___ 1

1 answer:

3 0

To solve these types of problems, we need to convert the two values into the same form.

We know that 1 = 1.00, as adding zeroes to the end of a decimal doesn't change the value.

To change a decimal into a percentage, we multiply the decimal by 100 and add a percent sign.

1.00 * 100 = 100%

Therefore, 1 = 100%

Because 120% is greater than 100%, thus,

120% > 1

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Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

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Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

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$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

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3 years ago

Help plz most of points!

dmitriy555 [2]

First, we need to know how much profit in dollar value by this method
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Plug in the numbers to the formula above
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Second, add the original price and the profit together and you'll find the new price.
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new price = $25 + $10
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