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Goryan [66]
3 years ago
5

Complete the following equation using <, >, or = 120% ___ 1

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
To solve these types of problems, we need to convert the two values into the same form.  

We know that 1 = 1.00, as adding zeroes to the end of a decimal doesn't change the value.

To change a decimal into a percentage, we multiply the decimal by 100 and add a percent sign.  

1.00 * 100 = 100%

Therefore, 1 = 100%

Because 120% is greater than 100%, thus, 

120% > 1
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Step-by-step explanation:

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Talja [164]

Answer:

C) 58

Step-by-step explanation:

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7 0
3 years ago
Find all of the zeros of the function f(x) = x^3 + 5x^2 + 6x. If there is more than one answer, enter your answers as a comma se
suter [353]
<h2>Answer:</h2>

There are more than one zero i.e. three zeros of the given polynomial.

            The zeros are:

                        x=0,-2,-3

<h2>Step-by-step explanation:</h2>

We are given a function f(x) by:

             f(x)=x^3+5x^2+6x

We know that the zeros of the function f(x) are the possible values of x at which the function is equal to zero.

Hence, when f(x)=0 we have:

x^3+5x^2+6x=0\\\\i.e.\\\\x^3+3x^2+2x^2+6x=0\\\\i.e.\\\\x^2(x+3)+2x(x+3)=0\\\\i.e.\\\\(x^2+2x)(x+3)=0\\\\x(x+2)(x+3)=0\\\\i.e.\\\\x=0\ or\ x=-2\ or\ x=-3

7 0
3 years ago
An atomic nucleus has a charge of +40e. What is the magnitude of the electric field at a distance of 1.0 m from the center of th
ASHA 777 [7]

Answer:

E=5.76\times 10^{-8}N/C

Step-by-step explanation:

We are given that

Charge of atomic nucleus,q=+40 e=40\times 1.6\times 10^{-19}C

Because

1 e=1.6\times 10^{-19} C

Charge of atomic nucleus=64\times 10^{-19}C

Distance of charge form the center of nucleus=r=1 m

We have to find the magnitude of  electric field at distance r

E=\frac{Kq}{r^2}

Where K=9\times 10^9Nm^2/C^2

Using the formula

E=\frac{9\times 10^9\times 64\times 10^{-19}}{1}=576\times 10^{-10}N/C

E=\frac{576}{100}\times 10^2\times 10^{-10}=5.76\times 10^{2-10}=5.76\times 10^{-8}N/C

Using identitya^x\cdot a^y=a^{x+y}

Hence, the magnitude of electric field=E=5.76\times 10^{-8}N/C

6 0
3 years ago
Determine the intercepts of the line y+1=3(x-4)
stich3 [128]

To find the intercepts, the other number will be 0 (x-intercept: when y is 0, and vise-versa).

So:

x-intercept: <u><em>0</em></u><em> + 1 = 3x - 12 -> 3x = 13 -> </em><em>x = 13/3</em><em>, </em>so it will be<em> </em>(\frac{13}{3}, 0)<em>.</em>

y-intercept:<em> y + 1 = 3*</em><u><em>0</em></u><em> - 12 -> </em><em>y = -13</em>, so it will be (0, -13).

5 0
3 years ago
Read 2 more answers
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