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Radda [10]
3 years ago
13

A 0.2-kilogram red ball is thrown horizontally at a speed of 4 meters per second from a height of 3 meters. A 0.4-kilogram green

ball is thrown horizontally from the same height at a speed of 8 meters per second. Compared to the time it takes the red ball to reach the ground, the time it takes the green ball to reach the ground is (A) four times as great (C) the same (B) twice as great (D) one-half as great
Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

option (C) the same

Step-by-step explanation:

In the given question , it is mentioned that the ball of mass 0.2 kilograms is thrown with the velocity of 4 m/s in the horizontal direction

and, the 0.4 kilogram green ball is thrown in the horizontal direction with the velocity of 8 m/s

Here in both the cases no component of velocity in the vertical direction is provided.

Hence, it will be a case of free fall in the vertical direction.

Now,

from Newton's equation of motion, we have

s=ut+\frac{1}{2}at^2

here,  

s is the distance

a is the acceleration

t is the time

in the above equation, mass has no role and the value of acceleration i.e acceleration due to gravity and distance of fall in the vertical direction is same.

Hence, the time taken for both the balls will be same.

Hence,

The correct answer is option (C) the same

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Answer:

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Step-by-step explanation:

The common difference in this arithmetic sequence is 13.  This is obtained by subtracting 28 from 41.  The first term is a(1) = -28.

The arithmetic sequence formula is a(n) = a(1) + d(n - 1), where d is the common difference and -28 the first term.

Then, in this case, a(n) = -28 - 13(n - 1), and

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