A wooden log of density 2g/cm3 and volume 50 cm3 fall on the surface of water. Calculate its buoyant force.
1 answer:
Answer:
The buoyant force =98 N (OPTION A)
Explanation:
Buoyant force refers to whether an object can float in water or air caused by the upward force exerted on a submerged object, which is equal to the weight of the fluid displaced.
Buoyant force is given by:
Fbuoyant = PA
Where, P = pressure
A = area
While, in a situation where there is volume, area and height involved we have:
Fbuoyant = pgha = gpv
Where, p = density of the fluid
g = gravity
h = height of immersed part
a = area
v = volume of immersed part of the body of the fluid
given data:
density = 2g/cm3
volume = 50 cm3
Fbuoyant = gpv
= (9.8m/s²) x (2 x 10∧ x 10∧
Kg/m³) x (50 x 10∧-
m²) = 98 N
Where, gravity = 9.8m/s²
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