Question

A wooden log of density 2g/cm3 and volume 50 cm3 fall on the surface of water. Calculate its buoyant force.

Answer 1

Answer:

The buoyant force =98 N (OPTION A)

Explanation:

Buoyant force refers to whether an object can float in water or air caused by the upward force exerted on a submerged object, which is equal to the weight of the fluid displaced.

Buoyant force is given by:

Fbuoyant = PA

Where, P = pressure

          A = area

While, in a situation where there is volume, area and height involved we have:

Fbuoyant = pgha = gpv

Where, p = density of the fluid

        g = gravity

         h = height of immersed part

         a = area

         v = volume of immersed part of the body of the fluid

given data:

density = 2g/cm3

volume = 50 cm3

Fbuoyant = gpv

  = (9.8m/s²) x (2 x 10∧$-^{3}$ x 10∧$^{6}$ Kg/m³)  x (50 x 10∧-$^{4}$ m²) = 98 N

Where, gravity = 9.8m/s²