A wooden log of density 2g/cm3 and volume 50 cm3 fall on the surface of water. Calculate its buoyant force.
1 answer:
Answer:
The buoyant force =98 N (OPTION A)
Explanation:
Buoyant force refers to whether an object can float in water or air caused by the upward force exerted on a submerged object, which is equal to the weight of the fluid displaced.
Buoyant force is given by:
Fbuoyant = PA
Where, P = pressure
A = area
While, in a situation where there is volume, area and height involved we have:
Fbuoyant = pgha = gpv
Where, p = density of the fluid
g = gravity
h = height of immersed part
a = area
v = volume of immersed part of the body of the fluid
given data:
density = 2g/cm3
volume = 50 cm3
Fbuoyant = gpv
= (9.8m/s²) x (2 x 10∧ x 10∧
Kg/m³) x (50 x 10∧-
m²) = 98 N
Where, gravity = 9.8m/s²
You might be interested in
Answer:
T=1022.42 N
Explanation:
Given that
l = 32 cm ,μ = 1.5 g/cm
L =2 m ,V= 344 m/s
The pipe is closed so n= 3 ,for first over tone
f= 129 Hz
The tension in the string given as
T = f²(4l²) μ
Now by putting the values
T = f²(4l²) μ
T = 129² x (4 x 0.32²) x 1.5 x 10⁻³ x 100
T=1022.42 N
Answer:
Pressure (P) is the amount of force applied perpendicular to the surface of an object per unit area. The SI unit of pressure is the pascal (Pa), which is equivalent to N/ (newtons per meter squared).