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Darya [45]
3 years ago
15

How do you make a mirages?​

Physics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer:

when the ground is very hot and the air is cool.

Explanation:

The hot earth warms a layer of air right above the ground. Light is refracted as it passes through the cool air and onto the hot air sheet (bent). A coating of very warm air near the earth bends the light from the sky almost into a U-shaped bend.

vampirchik [111]3 years ago
3 0

Answer: when the ground is very hot and the air is cool. The hot ground warms a layer of air just above the ground. When the light moves through the cold air and into the layer of hot air it is refracted (bent). A layer of very warm air near the ground refracts the light from the sky nearly into a U-shaped bend.

Explanation:

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On top of Mount Everest, the temperature is -19 ∘C in July. Being a physicist, you determine by how many degrees Celsius one nee
kondaur [170]

Answer:

254 °C

Explanation:

The average kinetic energy of gas molecules K = 3RT/2N where R = gas constant = 8.314 J/mol-K, N = avogadro's constant = 6.022 × 10²³ atoms/mol

T = temperature in Kelvin.

Let K be its average kinetic energy at t = -19°C = 273 + (-19) = 273 - 19 = 254 K = T. K = 3RT/2N = 3 × 8.314 J/mol-K × 254 K/(2 × 6.022 × 10²³ atoms/mol) = 5.26 × 10⁻²¹ J

When its average kinetic energy doubles, it becomes K₁ = 2K = 2 × 5.26 × 10⁻²¹ = 10.52 × 10⁻²¹ J at temperature T₂. So,

K₁ = 3RT₁/2N

T₁ = 2NK₁/3R

T₁ = 2 × 6.022 × 10²³ atoms/mol × 10.52 × 10⁻²¹ J/3 × 8.314 J/mol-K = 508 K

The temperature difference is thus ΔT = T₁ - T = 508 K - 254 K = 254 K.

Since temperature change in kelvin scale equals temperature change in Celsius scale ΔT = 254 °C

So, we need to change the temperature of the air by 254 °C to double its average kinetic energy.

3 0
3 years ago
What is the electric force acting between two charges of -0.0050 C and
love history [14]

The electric force is -3.6\cdot 10^8 N (attractive)

Explanation:

The magnitude of the electric force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, we have the following:

q_1 = -0.0050 C (charge 1)

q_2 = +0.0050 C (charge 2)

r = 0.025 m (distance)

Substituting, we find the electric force between the two charges:

F=(9\cdot 10^9) \frac{(-0.0050)(0.0050)}{(0.025)^2}=-3.6\cdot 10^8 N

And the negative sign means the force is attractive, since the two charges have opposite sign.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0
3 years ago
The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent ho
faltersainse [42]

Answer:

Explanation:

Let mass of cylinder be M

Moment of inertia of cylinder

= 1/2 M R² r is radius of cylinder

If radius of equivalent  hoop be k

Mk² = 1/2 x MR²

k = R / √2

1.2 / 1.414

Radius of gyration = 0.848 m

b )

moment of inertia of spherical shell

= 2 / 3 M R²

Moment of inertia of equivalent hoop

Mk²

So

Mk² = 2 / 3 M R²

k = √2/3 x R

= .816 X 1.2

Radius of gyration = .98 m

c )

Moment of inertia of solid sphere

= 2/5 M R²

Moment of inertia of equivalent hoop

= Mk²

Mk² = 2/5 M R²

k √ 2/5 R

Radius of gyration = .63 R

6 0
4 years ago
When a ball player throws a ball straight up, by how much does the speed of the ball decrease each second while ascending?
Alexxandr [17]
-9.8 m/s^s because thats the earth gravity so it will lose 9.8 m/s^2 until its stop and thats because its the opposite of the force towards the earth!
Hope it helps
6 0
3 years ago
A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?
Advocard [28]

Answer:

v=697.2km/h

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

V=\frac{d}{t}

The distance is clearly 1743 km and the time is:

t=2h+30min*\frac{1h}{60min} =2.5h

Thus, the velocity turns out:

v=\frac{1743km}{2.5h}\\ \\v=697.2km/h

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

5 0
3 years ago
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