Answer:
254 °C
Explanation:
The average kinetic energy of gas molecules K = 3RT/2N where R = gas constant = 8.314 J/mol-K, N = avogadro's constant = 6.022 × 10²³ atoms/mol
T = temperature in Kelvin.
Let K be its average kinetic energy at t = -19°C = 273 + (-19) = 273 - 19 = 254 K = T. K = 3RT/2N = 3 × 8.314 J/mol-K × 254 K/(2 × 6.022 × 10²³ atoms/mol) = 5.26 × 10⁻²¹ J
When its average kinetic energy doubles, it becomes K₁ = 2K = 2 × 5.26 × 10⁻²¹ = 10.52 × 10⁻²¹ J at temperature T₂. So,
K₁ = 3RT₁/2N
T₁ = 2NK₁/3R
T₁ = 2 × 6.022 × 10²³ atoms/mol × 10.52 × 10⁻²¹ J/3 × 8.314 J/mol-K = 508 K
The temperature difference is thus ΔT = T₁ - T = 508 K - 254 K = 254 K.
Since temperature change in kelvin scale equals temperature change in Celsius scale ΔT = 254 °C
So, we need to change the temperature of the air by 254 °C to double its average kinetic energy.
The electric force is 
(attractive)
Explanation:
The magnitude of the electric force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have the following:
(charge 1)
(charge 2)
r = 0.025 m (distance)
Substituting, we find the electric force between the two charges:
And the negative sign means the force is attractive, since the two charges have opposite sign.
Learn more about electric force:
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Answer:
Explanation:
Let mass of cylinder be M
Moment of inertia of cylinder
= 1/2 M R² r is radius of cylinder
If radius of equivalent hoop be k
Mk² = 1/2 x MR²
k = R / √2
1.2 / 1.414
Radius of gyration = 0.848 m
b )
moment of inertia of spherical shell
= 2 / 3 M R²
Moment of inertia of equivalent hoop
Mk²
So
Mk² = 2 / 3 M R²
k = √2/3 x R
= .816 X 1.2
Radius of gyration = .98 m
c )
Moment of inertia of solid sphere
= 2/5 M R²
Moment of inertia of equivalent hoop
= Mk²
Mk² = 2/5 M R²
k √ 2/5 R
Radius of gyration = .63 R
-9.8 m/s^s because thats the earth gravity so it will lose 9.8 m/s^2 until its stop and thats because its the opposite of the force towards the earth!
Hope it helps
Answer:
Explanation:
Hello.
In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:
The distance is clearly 1743 km and the time is:
Thus, the velocity turns out:
Which is a typical velocity for a plane to allow it be stable when flying.
Best regards.
