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shepuryov [24]
3 years ago
7

Question 8 of 25

Physics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

A. They use X-rays that penetrate most objects.

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Svetllana [295]

C. The range of a projectile increases with an increase in the angle of launch.

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Difinition of gravity
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it's all around you and it can't be destroyed

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Which of the following statements is TRUE about updating the exposure control plan?
iren2701 [21]

Statements that are true as regards exposure control plan and its updating are;

<em>Updates must have the  reflection of changes in tasks as well in procedures.</em>

<em>Updates must reflect changes in positions that affect occupational exposure.</em>

<em>Updates must have the cost of PPE that is needed and  necessary to reduce exposure</em>

An exposure control plan can be regarded as  the framework for compliance between the employer and the workers.

  • This framework give room for the employer to creates a written plan that will help in protecting their workers from bloodborne pathogens.

  • This plan gives hope to workers in term of protection when working with their Employer.

  • There are some elements that is associated with  Exposure Control Plan, and theses are;
  1. Health hazards as well as  risk that is attributed to  each product in the worksite.
  2. Statement of purpose.
  3. procedures and practices in a written form
  4. Responsibilities from the Manager, CEO, designated resources and employer.

Therefore, exposure control plan is avenue to protect workers from bloodborne pathogens.

brainly.com/question/1203927?referrer=searchResults

3 0
2 years ago
An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing
exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

7 0
3 years ago
Will the velocity of the book change as it moves across the surface with NO friction? Explain your answer.
MakcuM [25]

No velocity will not be changed

Why?

According to Newtons 1st law the velocity of a moving object remains unchanged unless a external force affect that.

6 0
2 years ago
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